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4.9x^2-24x+11=0
a = 4.9; b = -24; c = +11;
Δ = b2-4ac
Δ = -242-4·4.9·11
Δ = 360.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-\sqrt{360.4}}{2*4.9}=\frac{24-\sqrt{360.4}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+\sqrt{360.4}}{2*4.9}=\frac{24+\sqrt{360.4}}{9.8} $
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